50=-4.9x^2+100x+2

Solution for 50=-4.9x^2+100x+2 equation:

50=-4.9x^2+100x+2

We move all terms to the left:

50-(-4.9x^2+100x+2)=0

We get rid of parentheses

4.9x^2-100x-2+50=0

We add all the numbers together, and all the variables

4.9x^2-100x+48=0

a = 4.9; b = -100; c = +48;
Δ = b2-4ac
Δ = -1002-4·4.9·48
Δ = 9059.2
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-100)-\sqrt{9059.2}}{2*4.9}=\frac{100-\sqrt{9059.2}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-100)+\sqrt{9059.2}}{2*4.9}=\frac{100+\sqrt{9059.2}}{9.8}
$